From 27fddb260efbfb0e2d8898502cc3738d0662fba5 Mon Sep 17 00:00:00 2001
From: Austin King <shout@ozten.com>
Date: Wed, 18 Jan 2012 15:50:17 -0800
Subject: [PATCH] Removing copy of GPL Gettext.js strargs function

---
 lib/i18n.js | 53 ++---------------------------------------------------
 1 file changed, 2 insertions(+), 51 deletions(-)

diff --git a/lib/i18n.js b/lib/i18n.js
index d365aaf9e..32daab9f5 100644
--- a/lib/i18n.js
+++ b/lib/i18n.js
@@ -180,57 +180,8 @@ exports.localeFrom = localeFrom = function (language) {
 };
 
 /**
- * Copied from `resources/static/shared/gettext.js`, so we can use the
- * same method name on node.js and client-side.
+ * TODO: replace with util.format like function
  */
 exports.strargs = strargs = function (str, args) {
-    // make sure args is an array
-    if ( null == args ||
-         'undefined' == typeof(args) ) {
-        args = [];
-    } else if (args.constructor != Array) {
-        args = [args];
-    }
-
-    // NOTE: javascript lacks support for zero length negative look-behind
-    // in regex, so we must step through w/ index.
-    // The perl equiv would simply be:
-    //    $string =~ s/(?<!\%)\%([0-9]+)/$args[$1]/g;
-    //    $string =~ s/\%\%/\%/g; # restore escaped percent signs
-
-    var newstr = "";
-    while (true) {
-        var i = str.indexOf('%');
-        var match_n;
-
-        // no more found. Append whatever remains
-        if (i == -1) {
-            newstr += str;
-            break;
-        }
-
-        // we found it, append everything up to that
-        newstr += str.substr(0, i);
-
-        // check for escpaed %%
-        if (str.substr(i, 2) == '%%') {
-            newstr += '%';
-            str = str.substr((i+2));
-
-        // % followed by number
-        } else if ( match_n = str.substr(i).match(/^%(\d+)/) ) {
-            var arg_n = parseInt(match_n[1]);
-            var length_n = match_n[1].length;
-            if ( arg_n > 0 && args[arg_n -1] != null && typeof(args[arg_n -1]) != 'undefined' )
-                newstr += args[arg_n -1];
-            str = str.substr( (i + 1 + length_n) );
-
-        // % followed by some other garbage - just remove the %
-        } else {
-            newstr += '%';
-            str = str.substr((i+1));
-        }
-    }
-
-    return newstr;
+  return str;
 };
\ No newline at end of file
-- 
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